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AMC 10 & 12

Linear Equations & Inequalities

Solving single-variable equations and reading inequality solutions as intervals — simple mechanics, but the source of a surprising number of careless errors.

Linear equations are the easiest algebra on the AMC, which is exactly why they cause avoidable point losses: under time pressure, people rush and flip a sign. This lesson is short on purpose — the goal is precision, not new ideas.

Solving linear equations

Any equation of the form ax+b=0ax + b = 0 with a0a \neq 0 has exactly one solution:

x=bax = -\dfrac{b}{a}

Most AMC linear equations are just this idea wrapped in extra algebra — clear denominators first, expand, collect like terms on one side, then divide.

Inequalities and interval notation

Solving a linear inequality works exactly like solving an equation, with one rule that catches people constantly: multiplying or dividing both sides by a negative number flips the inequality sign.

2x<6        x>3-2x < 6 \;\;\Longrightarrow\;\; x > -3

Solutions are usually reported as intervals. A round bracket/parenthesis means the endpoint is excluded (strict inequality); a square bracket means it's included:

  • x>ax > a is the interval (a,)(a, \infty)
  • xax \leq a is the interval (,a](-\infty, a]
  • a<xba < x \leq b is the interval (a,b](a, b]

A compound inequality (two inequalities chained together, or an “and”/“or” combination of two separate ones) is solved by handling each piece separately and then intersecting (for “and”) or taking the union (for “or”) of the resulting intervals.

Worked example

Problem: Solve 523x<7-5 \leq 2 - 3x < 7 and express the answer in interval notation.

Solution: Subtract 2 from all three parts: 73x<5-7 \leq -3x < 5. Now divide everything by −3, remembering to flip both inequality signs:

73x>53\dfrac{7}{3} \geq x > -\dfrac{5}{3}

Rewriting with the smaller value first: 53<x73-\tfrac{5}{3} < x \leq \tfrac{7}{3}, i.e. the interval (53, 73]\left(-\tfrac{5}{3},\ \tfrac{7}{3}\right].

Practice problems

1.Solve for xx: 3(x4)=2x+53(x-4) = 2x + 5.

2.Solve and write in interval notation: 4x2x54 - x \geq 2x - 5.

3.Solve: 3<x+124-3 < \dfrac{x+1}{2} \leq 4.

4.For which values of xx is 4x+1<9-4x + 1 < 9 false?