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AMC 10 & 12

Systems of Equations

Substitution, elimination, and — for the harder problems — exploiting symmetry to avoid solving for each variable individually.

Linear systems

Two standard tools for a linear system in two variables:

  • Substitution — solve one equation for one variable, plug into the other.
  • Elimination — scale the equations so a variable's coefficients match (or are opposite), then add or subtract to cancel it.

A linear system can have exactly one solution, no solutions (parallel, inconsistent lines), or infinitely many (the same line written twice) — worth a half-second sanity check before you commit to solving.

Nonlinear systems

When one equation is a line and the other is a circle or parabola, substitution is almost always the move: solve the linear equation for one variable, substitute into the nonlinear one, and you're left with a single-variable equation (often quadratic).

The symmetry shortcut

When a system is symmetric in xx and yy — meaning it's built fromx+yx+y, xyxy, and x2+y2x^2+y^2 rather than xx and yyindividually — it's often much faster to solve for the symmetric combinations directly using the identity x2+y2=(x+y)22xyx^2+y^2 = (x+y)^2 - 2xy, rather than solving for xx and yyseparately.

Worked example

Problem: If x+y=7x + y = 7 and x2+y2=29x^2 + y^2 = 29, find xyxy.

Solution: Use x2+y2=(x+y)22xyx^2+y^2 = (x+y)^2 - 2xy:

29=722xy=492xy    2xy=20    xy=1029 = 7^2 - 2xy = 49 - 2xy \;\Longrightarrow\; 2xy = 20 \;\Longrightarrow\; xy = 10

Found directly, with no need to solve the underlying quadratic for xx and yyindividually (they turn out to be 5 and 2, but we never had to find that).

Practice problems

1.Solve the system: 2x+y=112x + y = 11, xy=1x - y = 1.

2.Solve: y=x+1y = x + 1 and x2+y2=25x^2+y^2=25.

3.If x+y=6x+y=6 and xy=5xy=5, find x2+y2x^2+y^2.

4.Solve: 3x2y=43x - 2y = 4, 6x4y=86x - 4y = 8. What kind of system is this?